To find the x-intercepts of the function \( f(x) = 2x - 2 \), we need to set the equation equal to zero and solve for \( x \):
\[ 2x - 2 = 0 \]
Adding 2 to both sides gives:
\[ 2x = 2 \]
Dividing both sides by 2 yields:
\[ x = 1 \]
This means the function has an x-intercept at \( (1, 0) \).
Now, let's evaluate whether there is an x-intercept at \( (0, 0) \):
\[ f(0) = 2(0) - 2 = -2 \]
Since \( f(0) \) is not equal to 0, there is no x-intercept at \( (0, 0) \).
Thus, the claim that the x-intercepts of the graph are \( (0, 0) \) and \( (1, 0) \) is false. The only x-intercept is \( (1, 0) \).
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