Take a look here. It's almost the same.
http://www.jiskha.com/display.cgi?id=1489212302
f(x) = -2x^2+4x+1
Can someone explain how the f(x) is worked into this function?
I am supposed to graph the function and find the vertex and the axis of symmetry.I'm a little lost no major.
2 answers
F(x) = Y = -2x^2 + 4x + 1.
a. h = Xv = -B/2A = -4/-4 = 1 = Axis of symmetry.
b. k = -2*1^2 + 4*1 + 1 = 3.
V(h,k) = (1,3).
c. Use the given Eq(Y = -2x^2+4x+1) to calculate "Y" for each value of "X" shown below.
(X,Y).
(-2,
(-1,
(0,1).
(1,3)V.
(2,
(3,
(4,
Use the above points for graphing.
a. h = Xv = -B/2A = -4/-4 = 1 = Axis of symmetry.
b. k = -2*1^2 + 4*1 + 1 = 3.
V(h,k) = (1,3).
c. Use the given Eq(Y = -2x^2+4x+1) to calculate "Y" for each value of "X" shown below.
(X,Y).
(-2,
(-1,
(0,1).
(1,3)V.
(2,
(3,
(4,
Use the above points for graphing.
5 answers