To find the x-intercepts of the function \( f(x) = 2x^2 - 2x \), we need to set \( f(x) = 0 \) and solve for \( x \).
Setting the equation to zero:
\[ 2x^2 - 2x = 0 \]
Factoring out the common term:
\[ 2x(x - 1) = 0 \]
This gives us two factors:
- \( 2x = 0 \) → \( x = 0 \)
- \( x - 1 = 0 \) → \( x = 1 \)
So the x-intercepts are \( (0, 0) \) and \( (1, 0) \).
Therefore, the statement is true.