f(x)=2x^2-2x

True or false
The x intercepts of this graph are (0,0) and (1,0)

1 answer

To find the x-intercepts of the function \( f(x) = 2x^2 - 2x \), we need to set \( f(x) = 0 \) and solve for \( x \).

Setting the equation to zero:

\[ 2x^2 - 2x = 0 \]

Factoring out the common term:

\[ 2x(x - 1) = 0 \]

This gives us two factors:

  1. \( 2x = 0 \) → \( x = 0 \)
  2. \( x - 1 = 0 \) → \( x = 1 \)

So the x-intercepts are \( (0, 0) \) and \( (1, 0) \).

Therefore, the statement is true.