I will assume you want f(x)
f ''(x) = 20x3 + 12x2 + 10
then f'(x) = 5x^4 + 3x^4 + 10x + c
f(x) = x^5 + (3/5)x^4 + 5x^2 + cx + d
f(0) = 7 ---> 7 = 0+0+0+0+d ----------> d = 7
then f(x) = x^5 + (3/5)x^4 + 5x^2 + cx + 7
f(1) = 9 ---> 9 = 1 + 3/5 + 5 + c + 7
c = -23/5
f(x) = x^4 + (3/5)x^4 + 5x^2 - (23/5)x + 7
f ''(x) = 20x3 + 12x2 + 10, f(0) = 7, f(1) = 9
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