f(x) = 10(2)^x

Question

Is this function's rate of change over the interval -1 ≤ x ≤ 2 greater or less than that of the linear function g(x)=10x + 7?

--

What is this problem asking me to do and how do I do it?

Answer 1

I would interpret it this way,

Average rate of change for first function:
f(-1) = 10(1/2) = 5
f(2) = 10(2^2) = 40
avg rate of change = (40 - 5)/(2-(-1)) = 35/3 or appr 11.666...

rate of change of second function y = 10x+7 is constant at 10

so what do you think?

Answer 2

no clue