you can first find g(3) = 10
then do f(1) = 1/10
so g(g(3)) = 1/10
you try the other one.
another way is to find f(g(x)) itself.
this would be practical if you had a whole bunch of question to find
f(g(x))
= 1/(3x+1)
notice the right side gives you 1/10 directly
f(x)=1/x, g(x)=3X+1 find:
f(g(3)) how do i do thiss...
f(g(-2))
g.g, g.f, f.g, pleaseee help:)thanks for your timeee
3 answers
my third line should have said
f(g(3)) = 1/10
for your last part,
e.g. gºg would mean g(g(x))
= 3(3x+1) + 1
= 9x+ 4
f(g(3)) = 1/10
for your last part,
e.g. gºg would mean g(g(x))
= 3(3x+1) + 1
= 9x+ 4
OHHH thanks reiniyyyy