f(x)= 1/4 * (sin2x)^2
find dy/dx
d/dx (1/4 * (sin2x)^2)= (sin2xcos2x)/ 2 ?
2 answers
wait no its just (sin2xcos2x)
Tom's last answer is correct
or
(1/2)sin(4x)
or
(1/2)sin(4x)