The given function is F:W=X√(-x-2) and the domain is {-1, 0, 2, 5, 11}.
To find the corresponding range values, substitute each value from the domain into the function and evaluate it.
1. For x = -1:
F (-1) = (-1)√[-(-1)-2]
F (-1) = (-1)√[1-2]
F (-1) = (-1)√[-1]
F (-1) = i
2. For x = 0:
F (0) = (0)√[-(0)-2]
F (0) = (0)√[0-2]
F (0) = (0)√[-2]
F (0) = 0
3. For x = 2:
F (2) = (2)√[-(2)-2]
F (2) = (2)√[-4]
F (2) = 2i
4. For x = 5:
F (5) = (5)√[-(5)-2]
F (5) = (5)√[-7]
F (5) = 5√(-7)
5. For x = 11:
F (11) = (11)√[-(11)-2]
F (11) = (11)√[-13]
F (11) = 11√(-13)
Therefore, the range of the function for the given domain is {i, 0, 2i, 5√(-7), 11√(-13)}.
F:W=X√-x-2{-1,0,2,5,11} pls the topic functions is in further mathematics
5 answers
What is the √-1
The square root of -1 is represented by the imaginary unit, denoted as "i". So, √(-1) = i.
-1×-1 is what
-1×-1 equals 1.