f(t)=1/3(t+145)^2 - 67

Question

Find the inverse?

is it

t=1/3(f+145)^2-67

Answer 1

No. Solve for t in terms of f, and then switch variables to write it in f^-1(t) form.

Is the 1/3 a multiplier of (t+145)^2, or is (t+145)^2 part of the denominator? You need to be clearer about that, using extra paretheses if necessary.