f=p(c-1)-c(p-1)

Question

sOLVE FOR p

f=pc-p-cp+c

pc - cp = 0

So now we have f = -p+c

Move "p" by itself.

f-c = -p

Now we multiply each side by -1

p = c-f

Let's plug in values for f and c to check. We'll say:

f=2
c=3

p=3-2

p=1 in this case. Now, let's plug in the same values in the original equation.

2=p(3-1)-3(p-1)
2=3p-p-3p+3
2-3=-p

-1=-p

OR
1=p

So the answer: p=c-f

Took me forever to figure that out since I forgot to chance a negative to a positive when I multiplied. Glad I made it through though :)

Matt