f ln11≈2.398

and ln5≈1.609
, what is ln55
? Use the Product Rule of Logarithms to solve.(1 point)
Responses

1.490
1.490

3.858
3.858

4.007
4.007

0.789

1 answer

To find \( \ln 55 \) using the Product Rule of Logarithms, you can express 55 as the product of 11 and 5:

\[ \ln 55 = \ln(11 \times 5) \]

According to the Product Rule of Logarithms:

\[ \ln(a \times b) = \ln a + \ln b \]

Applying this to our expression gives:

\[ \ln 55 = \ln 11 + \ln 5 \]

Now, we can substitute the given values:

\[ \ln 11 \approx 2.398 \] \[ \ln 5 \approx 1.609 \]

Adding these together:

\[ \ln 55 \approx 2.398 + 1.609 \approx 4.007 \]

Therefore, the correct answer is:

4.007