To solve this equation, let's assign variables to each item:
🎹 = x
🎸 = y
🎷 = z
🎤 = w
Now let's solve each equation step by step:
Equation 1: 🎹 × 🎹 × 🎹 = 27
x × x × x = 27
x^3 = 27
Taking the cube root on both sides, we get:
x = 3
Equation 2: 🎹 × 🎸 = 🎷 × 🎤
x × y = z × w
Using the given values for y and w:
3 × 2 = z × 1
6 = z
Equation 3: 🎷 × 🎤 🎤× 🎷 = 6
z × w × w × z = 6
z^2 w^2 = 6
Using the given values for z and w:
6^2 × 1^2 = 6
36 = 6
This equation is not valid. There seems to be a mistake in the given values.
Equation 4: 🎷 - 🎹 = 🎹
z - x = x
Using the given values for z and x:
6 - 3 = 3
3 = 3
Equation 5: 🎹 🎸 × 🎷 × 🎤 = ♪ ❌ ✔️ ✔️ ✔️ ✔️
x × y × z × w = ♪ ❌ ✔️ ✔️ ✔️ ✔️
Using the given values for x, y, z, and w:
3 × 2 × 6 × 1 = ♪ ❌ ✔️ ✔️ ✔️ ✔️
36 = ♪ ❌ ✔️ ✔️ ✔️ ✔️
This equation is not valid. There seems to be a mistake in the given values.
To summarize, the values obtained for the variables are:
🎹 = 3
🎸 = 2
🎷 = 6
🎤 = 1
However, there seems to be inconsistencies in the given equations and values, particularly in equations 3 and 5. It is unclear how ♪, ❌, and ✔️ are related to the variables and their values. Additional information is needed to solve the equations accurately.
Extra Credit!%0D%0A🎹×🎹×🎹=27🎹×🎸=🎷×🎤🎤×🎷=6🎷−🎹=🎹🎸×🎷×🎤=♪❌✔%EF%B8%8F✔%EF%B8%8F✔%EF%B8%8F✔%EF%B8%8F%0D%0APicture%0D%0AValue%0D%0APiano 🎹%0D%0A9%0D%0AGuitar 🎸%0D%0A%0D%0A2%0D%0A3%E2%80%8B%0D%0A≈0.6667%0D%0ASaxophone 🎷%0D%0A18%0D%0AMicrophone 🎤%0D%0A%0D%0A1%0D%0A3%E2%80%8B%0D%0A≈0.3333%0D%0ANote ♪
1 answer