Hey Linus,
First step: simplify where you can. For example, equation 3 can be divided by 5, so you end up with (x3) + 2(x4) + 3(x6) = 1. Equation 4 can also be simplified. This will make the algebra later a little easier.
Second step: Pick an x (x1 seems to be a good one) to start solving, and begin moving around your equations.
Do you know where to go from here? (Or are you onto matrices already? If so ignore step 2 and build your matrix). If you're stuck show me what you've done so far and I'll help out!
Express the solutions of the following systems in terms of the free variables:
x1 + 3*(x2) - 2*(x3) + 2*(x5) = 0
2*(x1) + 6*(x2) - 5*(x3) - 2*(x4) + 4*(x5) - 3*(x6) = -1
5*(x3) + 10*(x4) + 15*(x6) = 5
2*(x1) + 6*(x2) + 8*(x4) + 4*(x5) + 18*(x6) = 6
2 answers
I got:
x1 = -3*(x2) -2*(x5) + 66*(x6) - 22
x2 = free
x3 = 33*(x6) - 11
x4 = -18*(x6) + 6
x5 = free
x6 = free
Is that correct?
x1 = -3*(x2) -2*(x5) + 66*(x6) - 22
x2 = free
x3 = 33*(x6) - 11
x4 = -18*(x6) + 6
x5 = free
x6 = free
Is that correct?
1 answer