Express the prime factorization of 128 as a product of a prime numbers with exponents

1 answer

To express the prime factorization of 128, we first need to factor it into its prime components.

128 can be broken down as follows:

  1. Start by dividing by 2 (the smallest prime number):
    • \( 128 \div 2 = 64 \)
  2. Continue dividing by 2:
    • \( 64 \div 2 = 32 \)
    • \( 32 \div 2 = 16 \)
    • \( 16 \div 2 = 8 \)
    • \( 8 \div 2 = 4 \)
    • \( 4 \div 2 = 2 \)
    • \( 2 \div 2 = 1 \)

Counting the number of times we divided by 2, we find that 128 is divided by 2 a total of 7 times.

Thus, the prime factorization of 128 is:

\[ 128 = 2^7 \]

So, the answer is \( 2^7 \).