To find the prime factorization of 1,200, we start with dividing it by the smallest prime numbers.
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Divide by 2:
- \(1200 \div 2 = 600\)
- \(600 \div 2 = 300\)
- \(300 \div 2 = 150\)
- \(150 \div 2 = 75\) (At this point 75 isn't divisible by 2, we switch to the next prime number)
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Divide by 3:
- \(75 \div 3 = 25\) (25 isn't divisible by 3, we switch to the next prime number)
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Divide by 5:
- \(25 \div 5 = 5\)
- \(5 \div 5 = 1\)
Putting it all together, we have:
- From 2, we divided 4 times: \(2^4\)
- From 3, we used it once: \(3^1\)
- From 5, we divided 2 times: \(5^2\)
Thus, the prime factorization of 1,200 is: \[ 1,200 = 2^4 \times 3^1 \times 5^2 \]
So, in the given format:
- \(2^4 \times 3^1 \times 5^2 = 1,200\)
Therefore, filling in the blanks: 2^4 x 3 x 5^2 = 1,200.