Express the following as a sum of partial fraction
2x+4÷x^2(x-2)
3 answers
Please give me a solution to this question
In google paste:
Partial fraction calculator
When you see list of results click on:
Partial Fraction Decomposition Calculator - eMathHelp
When page be open type numerator and denominator.
Then click option CALCULATE
You will see a solution step-by step
Partial fraction calculator
When you see list of results click on:
Partial Fraction Decomposition Calculator - eMathHelp
When page be open type numerator and denominator.
Then click option CALCULATE
You will see a solution step-by step
or, so you can do it on your own, you want to find
(2x+4)/(x^2(x-2)) = A/x + B/x^2 + C/(x-2)
so put the right side over the common denominator. That gives you
Ax(x-2) + B(x-2) + Cx^2 = 2x+4
Now expand and equate coefficients.
(A+C)x^2 + (-2A+B)x - 2B = 2x+4
A+C = 0
-2A+B = 2
-2B = 4
Solving that, you get
B = -2, A = -2, C = 2
(2x+4)/(x^2(x-2)) = -2/x - 2/x^2 + 2/(x-2)
(2x+4)/(x^2(x-2)) = A/x + B/x^2 + C/(x-2)
so put the right side over the common denominator. That gives you
Ax(x-2) + B(x-2) + Cx^2 = 2x+4
Now expand and equate coefficients.
(A+C)x^2 + (-2A+B)x - 2B = 2x+4
A+C = 0
-2A+B = 2
-2B = 4
Solving that, you get
B = -2, A = -2, C = 2
(2x+4)/(x^2(x-2)) = -2/x - 2/x^2 + 2/(x-2)