Express the concentration of a 0.0620M aqueous solution of fluoride, F-, in mass percentage and in parts per million. assume the density of the solution is 1.00g/mL.

Answer 1

0.0620M is 0.0620 mols/L solution.
g = mols x molar mass = 0.0620 x 19 = 1.18 g/L
mass% = (g solute/g solution)*100 =
(1.18/1000)*100 = ? = about 0.12 mass %.

A ppm is 1 mg/L so if we have 1.18g/L that is 1180 mg/L and that is 1180 ppm.
What the number of significant figures in the above, I didn't check them. Also, note I've estimated.