rationalize the denominator. I will do one:
(2+i)/(2-i)= 2+i)(2+i)/(2-i)(2+i)=
(2+i)^2/(2-i^2)= (4+4i+i^2)/3
you can complete it.
express the complex number in standard form(that is like a+bi)
1/2+i
2+i/2-i
4 answers
so is that the final answer
os is the final answer 8i+i^3/3
(2+i)/(2-i)
=(2+i)(2+i)/((2+i)(2-i))
=(4+4i+i²)/(2²-i²)
=(4+4i-1)/(4-(-1))
=(3+4i)/5
You can proceed along the same lines for the first problem.
=(2+i)(2+i)/((2+i)(2-i))
=(4+4i+i²)/(2²-i²)
=(4+4i-1)/(4-(-1))
=(3+4i)/5
You can proceed along the same lines for the first problem.