To simplify the expression \((\frac{3x+18}{4x+8}) \div (\frac{x^2-3}{6x+2})\), we start by rewriting it as a multiplication by the reciprocal:
\[ \frac{3x+18}{4x+8} \cdot \frac{6x+2}{x^2-3} \]
Next, we will simplify each part.
-
Simplifying \(3x + 18\): \[ 3x + 18 = 3(x + 6) \]
-
Simplifying \(4x + 8\): \[ 4x + 8 = 4(x + 2) \]
-
Simplifying \(6x + 2\): \[ 6x + 2 = 2(3x + 1) \]
-
Factoring \(x^2 - 3\) (this is already in simplest form, it is a difference of squares): \[ x^2 - 3 \text{ stays as it is.} \]
Now we can rewrite the entire expression with these factorizations:
\[ \frac{3(x+6)}{4(x+2)} \cdot \frac{2(3x+1)}{x^2-3} \]
Next, we can combine and multiply these fractions:
\[ \frac{3(x+6) \cdot 2(3x+1)}{4(x+2) \cdot (x^2-3)} \]
Now the numerator becomes:
\[ 6(x+6)(3x+1) \]
And the denominator is:
\[ 4(x+2)(x^2-3) \]
At this stage, check for any possible cancellations.
- No factors are common between the numerator and denominator that could be canceled at this point.
Therefore, we leave it as:
\[ \frac{6(x+6)(3x+1)}{4(x+2)(x^2-3)} \]
Finally, we can simplify \(6/4\) to \(3/2\):
\[ \frac{3(x+6)(3x+1)}{2(x+2)(x^2-3)} \]
This is the simplest form of the expression.
Thus, based on your options provided, none perfectly matches, but this is the simplest form of the expression.