it is wrong. What is the cube root of 27? Hint, it is not 9.
Secondly, the cube root of x^4 is x^(4/3)
Express cube root 27x^4y^6 using rational exponents
(27x^4y^6)1/3
(27^1/3)(x^4/3)(y^6/3)
stuck. I think the final answer is 9x^3/4(y^2) I don't know where to put the parentheses to break it up so I hope yall understand what it's suppose to be.
2 answers
By simplify: we get (27)^1/3 * (x^4)^1/3 * (y^6)^1/3 =3y^2x^4/3
2 answers