If you did problem 1, then just subtract that from the area of the whole circle.
If not, let's do it now. Recall that the area of the smaller segment is
a = 1/2 r^2 (θ-sinθ)
So, what's θ? Draw your diagram, and you can easily see that
sin(θ/2) = 4/8 = 1/2
θ = π/3
Plug that into the formula, and you will have the area of the smaller segment.
Express answer in exact form.
Find the area of the larger segment whose chord is 8" long in a circle with an 8" radius. (Hint: A chord divides a circle into two segments. In problem 1, you found the area of the smaller segment.)
I've no idea how to do this, please help me out if you could!
2 answers
Given a circle with an 8" radius, find the area of the smaller segment whose chord is 8" long