To express 108 as a product of prime factors, we can start by dividing it by the smallest prime numbers.
-
Divide by 2 (the smallest prime number): \( 108 \div 2 = 54 \)
-
Divide 54 by 2 again: \( 54 \div 2 = 27 \)
-
Now, divide 27 by 3 (the next smallest prime number): \( 27 \div 3 = 9 \)
-
Divide 9 by 3 again: \( 9 \div 3 = 3 \)
-
Finally, divide 3 by 3: \( 3 \div 3 = 1 \)
This gives us the prime factorization of 108 as: \[ 108 = 2^2 \times 3^3 \]
Thus, the product of primes of 108 is: \[ 2^2 \times 3^3 \]