Anatomic position is used as a standardized reference point in anatomy and physiology because it provides a consistent and common frame of reference for describing and studying the human body. This position serves as a universal starting point for communication and understanding among healthcare professionals, researchers, and anatomists.
Anatomic position is defined as follows:
- The person stands upright with their feet flat on the ground and parallel to each other.
- The arms are extended at the sides of the body, with the palms facing forward and the thumbs pointing away from the body.
- The head is held erect and facing forward.
Using anatomic position allows for accurate and consistent descriptions of anatomical structures and relationships. It eliminates confusion and ensures that everyone is on the same page when discussing the human body. For example, when referring to the location of an organ or a bone, it is essential to have a common reference point to avoid misunderstandings.
Anatomic position also aids in the understanding of anatomical terminology. Terms such as superior (above), inferior (below), anterior (front), and posterior (back) are based on the anatomic position. Without this standard position, it would be difficult to describe the relationship of various body parts accurately.
In addition, anatomic position provides an ideal and neutral starting point for conducting medical examinations and diagnostic procedures. Clinical assessments can be more precise when comparing a patient's position to the anatomic position. For instance, doctors can determine if a joint is flexed or extended by comparing it to the original position.
Overall, anatomic position is crucial for effective communication, accurate description, and standardized understanding of the human body's structure and function. It serves as a fundamental reference point, facilitating education, research, and healthcare practices.
Explain why anatomic position is used
15 answers
Evaluate the following expression when x = 5: 8(2x+6)
To evaluate the expression when x = 5, substitute 5 for x in the given expression:
8(2x + 6) = 8(2(5) + 6)
= 8(10 + 6)
= 8(16)
= 128
So, when x = 5, the expression 8(2x + 6) evaluates to 128.
8(2x + 6) = 8(2(5) + 6)
= 8(10 + 6)
= 8(16)
= 128
So, when x = 5, the expression 8(2x + 6) evaluates to 128.
Evaluate the following expression: 3x+6−y
when x = 2 and y = 5
when x = 2 and y = 5
To evaluate the expression when x = 2 and y = 5, substitute 2 for x and 5 for y in the given expression:
3x + 6 - y = 3(2) + 6 - 5
= 6 + 6 - 5
= 12 - 5
= 7
So, when x = 2 and y = 5, the expression 3x + 6 - y evaluates to 7.
3x + 6 - y = 3(2) + 6 - 5
= 6 + 6 - 5
= 12 - 5
= 7
So, when x = 2 and y = 5, the expression 3x + 6 - y evaluates to 7.
Evaluate the following expression: 5c−2k
when c = 7 and k = 3
when c = 7 and k = 3
To evaluate the expression when c = 7 and k = 3, substitute 7 for c and 3 for k in the given expression:
5c - 2k = 5(7) - 2(3)
= 35 - 6
= 29
So, when c = 7 and k = 3, the expression 5c - 2k evaluates to 29.
5c - 2k = 5(7) - 2(3)
= 35 - 6
= 29
So, when c = 7 and k = 3, the expression 5c - 2k evaluates to 29.
Evaluate the following expression: 2(k3+h−e)
when h = 18, k = 2, and e = 7
when h = 18, k = 2, and e = 7
To evaluate the expression when h = 18, k = 2, and e = 7, substitute these values into the given expression:
2(k^3 + h - e) = 2(2^3 + 18 - 7)
= 2(8 + 18 - 7)
= 2(26 - 7)
= 2(19)
= 38
So, when h = 18, k = 2, and e = 7, the expression 2(k^3 + h - e) evaluates to 38.
2(k^3 + h - e) = 2(2^3 + 18 - 7)
= 2(8 + 18 - 7)
= 2(26 - 7)
= 2(19)
= 38
So, when h = 18, k = 2, and e = 7, the expression 2(k^3 + h - e) evaluates to 38.
A soccer game is 90 minutes with m minutes of stoppage time. The total time is 90 + m. How long is the game with 23 minutes stoppage time?
To find the total time of the soccer game with 23 minutes of stoppage time, we substitute 23 for m in the expression 90 + m:
Total time = 90 + m
= 90 + 23
= 113
Therefore, the game with 23 minutes of stoppage time would be 113 minutes long.
Total time = 90 + m
= 90 + 23
= 113
Therefore, the game with 23 minutes of stoppage time would be 113 minutes long.
Marri bought 1/2
pound of licorice, 1/3
pound of candy worms, and 2/5
pound of jawbreakers. How many more pounds of licorice than candy worms did she buy?
pound of licorice, 1/3
pound of candy worms, and 2/5
pound of jawbreakers. How many more pounds of licorice than candy worms did she buy?
To find out how many more pounds of licorice Marri bought compared to candy worms, we need to subtract the amount of candy worms from the amount of licorice.
First, let's find the amount of licorice:
1/2 pound of licorice
Next, let's find the amount of candy worms:
1/3 pound of candy worms
To find the difference, we can subtract:
1/2 pound of licorice - 1/3 pound of candy worms
To perform the subtraction, we need a common denominator. The least common denominator of 2 and 3 is 6. So, we'll express the fractions with that denominator:
1/2 pound of licorice is equivalent to 3/6 pound.
1/3 pound of candy worms is equivalent to 2/6 pound.
Now we can subtract:
3/6 pound of licorice - 2/6 pound of candy worms
This gives us:
(3 - 2)/6 pound = 1/6 pound
Therefore, Marri bought 1/6 pound more licorice than candy worms.
First, let's find the amount of licorice:
1/2 pound of licorice
Next, let's find the amount of candy worms:
1/3 pound of candy worms
To find the difference, we can subtract:
1/2 pound of licorice - 1/3 pound of candy worms
To perform the subtraction, we need a common denominator. The least common denominator of 2 and 3 is 6. So, we'll express the fractions with that denominator:
1/2 pound of licorice is equivalent to 3/6 pound.
1/3 pound of candy worms is equivalent to 2/6 pound.
Now we can subtract:
3/6 pound of licorice - 2/6 pound of candy worms
This gives us:
(3 - 2)/6 pound = 1/6 pound
Therefore, Marri bought 1/6 pound more licorice than candy worms.
James and Luke took a two-day hike along the Appalachian Trial. The first day they hiked 4 1/6
miles and the second day they hiked 3 2/3
miles. What total distance did the boys hike?
miles and the second day they hiked 3 2/3
miles. What total distance did the boys hike?
To find the total distance James and Luke hiked over the two days, we need to add the distance hiked on the first day to the distance hiked on the second day.
First, let's find the distance hiked on the first day:
4 1/6 miles
Next, let's find the distance hiked on the second day:
3 2/3 miles
To add these fractions, we need a common denominator. The least common denominator of 6 and 3 is 6. So, we'll express the fractions with that denominator:
4 1/6 miles is equivalent to (4 * 6 + 1)/6 miles = 25/6 miles.
3 2/3 miles is equivalent to (3 * 6 + 2)/6 miles = 20/6 miles.
Now we can add:
25/6 miles + 20/6 miles = (25 + 20)/6 miles = 45/6 miles.
We can simplify this fraction by dividing the numerator and denominator by their greatest common divisor, which is 3:
45/6 miles simplifies to (45/3)/(6/3) = 15/2 miles.
Thus, James and Luke hiked a total distance of 15/2 miles, which is equivalent to 7 1/2 miles.
First, let's find the distance hiked on the first day:
4 1/6 miles
Next, let's find the distance hiked on the second day:
3 2/3 miles
To add these fractions, we need a common denominator. The least common denominator of 6 and 3 is 6. So, we'll express the fractions with that denominator:
4 1/6 miles is equivalent to (4 * 6 + 1)/6 miles = 25/6 miles.
3 2/3 miles is equivalent to (3 * 6 + 2)/6 miles = 20/6 miles.
Now we can add:
25/6 miles + 20/6 miles = (25 + 20)/6 miles = 45/6 miles.
We can simplify this fraction by dividing the numerator and denominator by their greatest common divisor, which is 3:
45/6 miles simplifies to (45/3)/(6/3) = 15/2 miles.
Thus, James and Luke hiked a total distance of 15/2 miles, which is equivalent to 7 1/2 miles.