let's complete the square to get it into standard form
12(x^2 - (3/2)x + .....) - 18(y^2 + (2/3)y + ...) = -12
12(x^2 - (3/2)x + 9/16) - 18(y^2 + (2/3)y + 1/9) = -12 + 9/16 + 1/9
12(x - 3/4)^2 - 18(y + 1/3)^2 = -1631/144
divide by 1631/144
(x-3/4)^2/(1728/1631) - (y+1/3)^2/(2592/1631) = -1
I am sure you can determine the properties of the vertical hyperbola from there.
Check my arithmetic.
Explain which conic section this equation and explain how to solve it:
12x^2-18y^2-18x-12y+12=0
1 answer
1 answer