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Explain using the dilution formula how to prepare 0.2m HCL acid from 37% HCL acidAsked by precious
Explain using the dilution formula how to prepare 0.2M HCL acid from 37% HCL acid
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Answered by
DrBob222
I looked up the density of a 37% solution at 20 degrees C = 1.18
Then 1000 x 1.18 x 0.37 x (1/36.45) = 12.3 M for the HCl.
Then mL1 x M1 = Ml2 x M2
mL1 x 12.3 = 1000 mL x 0.2 assuming you want to prepare 1000 mL of the solution. So you take mL1 you calculate, add to a 1000 mL volumetric flask, and add DI water to the mark of the volumetric flask. Mix thoroughly.
Then 1000 x 1.18 x 0.37 x (1/36.45) = 12.3 M for the HCl.
Then mL1 x M1 = Ml2 x M2
mL1 x 12.3 = 1000 mL x 0.2 assuming you want to prepare 1000 mL of the solution. So you take mL1 you calculate, add to a 1000 mL volumetric flask, and add DI water to the mark of the volumetric flask. Mix thoroughly.
Answered by
Suchita
How to prepare 0.2m hcl solution
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