s=3-2t+t^2
ds/dt=-2+2t
when it is not moving, ds/dt =0, solve for t.
y=(3x-1)/x= 3-1/x
dy/dx=+1/x^2
if slope is 7, then
7=1/x^2
x^2=1/7
x= sqrt(1/7)
y=(3x-1)/x solve for y.
Explain how to do these questions~
1. An object moves in a straight line with its position at time t seconds given by s(t) = 3-2t+t^2, where s is the measured in metres. At what time is the object not moving?
2. Determine the coordinates of the point(s) on the graph of y=3x- 1/x at which the slope of the tangent is 7.
4 answers
For number one we find the derivative of 3-2t+t^2
wouldn't that be t-2?
wouldn't that be t-2?
Oh crap nvm!
So for number 1 the answer is t=1
-2+2t=0
2t=2
2/2=1
-2+2t=0
2t=2
2/2=1