To expand the logarithm \( \ln\left(\frac{13}{x}\right) \), you can use the property of logarithms that states:
\[ \ln\left(\frac{a}{b}\right) = \ln(a) - \ln(b) \]
Applying this to your expression:
\[ \ln\left(\frac{13}{x}\right) = \ln(13) - \ln(x) \]
So, the correct response from your options is:
\[ \ln 13 - \ln x \]