To expand the expression \((4x - 1)(-3x^2 - 2x - 6)\), we will use the distributive property (also known as the FOIL method for binomials). Here’s how it works step by step:
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Distribute \(4x\) over \(-3x^2 - 2x - 6\): \[ 4x(-3x^2) + 4x(-2x) + 4x(-6) = -12x^3 - 8x^2 - 24x \]
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Distribute \(-1\) over \(-3x^2 - 2x - 6\): \[ -1(-3x^2) + (-1)(-2x) + (-1)(-6) = 3x^2 + 2x + 6 \]
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Combine the results from step 1 and step 2: \[ -12x^3 - 8x^2 - 24x + 3x^2 + 2x + 6 \]
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Combine like terms:
- For \(x^3\) terms: \(-12x^3\)
- For \(x^2\) terms: \(-8x^2 + 3x^2 = -5x^2\)
- For \(x\) terms: \(-24x + 2x = -22x\)
- For constant terms: \(6\)
Thus, the expanded polynomial in standard form is: \[ -12x^3 - 5x^2 - 22x + 6 \]