To expand the expression \((x - 9)(x^2 + x + 2)\), we will use the distributive property (often called the FOIL method for binomials).
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Distribute \(x\) across the second polynomial: \[ x \cdot (x^2) + x \cdot (x) + x \cdot (2) = x^3 + x^2 + 2x \]
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Distribute \(-9\) across the second polynomial: \[ -9 \cdot (x^2) + (-9) \cdot (x) + (-9) \cdot (2) = -9x^2 - 9x - 18 \]
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Now combine all the terms from both distributions: \[ x^3 + x^2 + 2x - 9x^2 - 9x - 18 \]
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Combine like terms:
- The \(x^2\) terms: \(x^2 - 9x^2 = -8x^2\)
- The \(x\) terms: \(2x - 9x = -7x\)
Putting it all together, we have: \[ x^3 - 8x^2 - 7x - 18 \]
So, the polynomial in standard form is: \[ \boxed{x^3 - 8x^2 - 7x - 18} \]