To expand the expression \((3x + 1)(3x^2 - 10x - 3)\), we will use the distributive property (often referred to as the FOIL method for binomials).
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Distribute \(3x\) across each term in the second polynomial: \[ 3x(3x^2) + 3x(-10x) + 3x(-3) = 9x^3 - 30x^2 - 9x \]
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Distribute \(1\) across each term in the second polynomial: \[ 1(3x^2) + 1(-10x) + 1(-3) = 3x^2 - 10x - 3 \]
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Combine all the expanded terms together: \[ 9x^3 - 30x^2 - 9x + 3x^2 - 10x - 3 \]
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Combine like terms:
- The \(x^2\) terms: \(-30x^2 + 3x^2 = -27x^2\)
- The \(x\) terms: \(-9x - 10x = -19x\)
- The constant term: \(-3\)
Putting it all together, we find: \[ 9x^3 - 27x^2 - 19x - 3 \]
Thus, the expanded polynomial in standard form is: \[ \boxed{9x^3 - 27x^2 - 19x - 3} \]