Expand the expression of log5x^(1/3)y^6

5 is the base of the log.
this is pretty tricky stuff and im not sure how to attempt it..

2 answers

Tricky?

1/3 log5 x + 6log5 y

Where is the trick?
Ok well bobpursley first of all your a genius ;) second of all im a newbie at this logorithm stuff. thank you for helping me!
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