Expand \(-\frac{5}{6}\left(9b-12\right)\). (1 point)

Answer 1

To expand \(-\frac{5}{6}(9b - 12)\), we will distribute \(-\frac{5}{6}\) to both terms inside the parentheses:

\[ -\frac{5}{6}(9b) - \frac{5}{6}(-12) \]

Calculating each term:

1. For the first term: \[ -\frac{5}{6} \cdot 9b = -\frac{45b}{6} = -\frac{15b}{2} \quad \text{(simplifying)} \]

2. For the second term: \[ -\frac{5}{6} \cdot (-12) = \frac{5 \cdot 12}{6} = \frac{60}{6} = 10 \]

Combining both results, we have:

\[ -\frac{15b}{2} + 10 \]

Thus, the expanded form is:

\[ -\frac{15b}{2} + 10 \]