Let's work through the expansion and simplification of the expression step by step.
Starting from the original expression: \[ -\frac{5}{7}(3x + \frac{1}{4}y) - 9\left(\frac{x}{7} - \frac{1}{28}y\right) \]
We'll expand each term separately.
Step 1: Expand the first term
\[ -\frac{5}{7}(3x) - \frac{5}{7}\left(\frac{1}{4}y\right) \] Calculating these:
- \(-\frac{5}{7} \cdot 3x = -\frac{15}{7}x\)
- \(-\frac{5}{7} \cdot \frac{1}{4}y = -\frac{5}{28}y\)
So, we have: \[ -\frac{15}{7}x - \frac{5}{28}y \]
Step 2: Expand the second term
\[ -9\left(\frac{x}{7}\right) - 9\left(-\frac{1}{28}y\right) \] Calculating these:
- \(-9 \cdot \frac{x}{7} = -\frac{9}{7}x\)
- \(-9 \cdot -\frac{1}{28}y = \frac{9}{28}y\)
So, we have: \[ -\frac{9}{7}x + \frac{9}{28}y \]
Step 3: Combine the results
Now we will combine the results from both expansions: \[ -\frac{15}{7}x - \frac{5}{28}y - \frac{9}{7}x + \frac{9}{28}y \]
Step 4: Combine the \(x\) terms and the \(y\) terms
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For the \(x\) terms: \[ -\frac{15}{7}x - \frac{9}{7}x = -\left(\frac{15 + 9}{7}\right)x = -\frac{24}{7}x \]
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For the \(y\) terms: \[ -\frac{5}{28}y + \frac{9}{28}y = \left(-5 + 9\right)\frac{1}{28}y = \frac{4}{28}y = \frac{1}{7}y \]
Thus, putting it all together, we have: \[ -\frac{24}{7}x + \frac{1}{7}y \]
The final simplified expression is: \[ -\frac{24}{7}x + \frac{1}{7}y \]