To expand \( 6(x + 1) \), you distribute the 6 to both terms inside the parentheses:
\[ 6(x + 1) = 6 \cdot x + 6 \cdot 1 \]
This simplifies to:
\[ 6x + 6 \]
So, the expanded form of \( 6(x + 1) \) is \( 6x + 6 \).
11 answers
To expand \( 6(x + 1) \), you distribute the 6 to both terms inside the parentheses:
\[ 6(x + 1) = 6 \cdot x + 6 \cdot 1 \]
This simplifies to:
\[ 6x + 6 \]
So, the expanded form of \( 6(x + 1) \) is \( 6x + 6 \).
The expanded form of \( 6(x + 1) \) is \( 6x + 6 \).
To expand \( 4(3z - 7) \), you distribute the 4 to both terms inside the parentheses:
\[ 4(3z - 7) = 4 \cdot 3z + 4 \cdot (-7) \]
This simplifies to:
\[ 12z - 28 \]
So, the expanded form of \( 4(3z - 7) \) is \( 12z - 28 \).
To expand \(-5(2q + 8)\), you distribute the \(-5\) to both terms inside the parentheses:
\[ -5(2q + 8) = -5 \cdot 2q + (-5) \cdot 8 \]
This simplifies to:
\[ -10q - 40 \]
So, the expanded form of \(-5(2q + 8)\) is \(-10q - 40\).
To expand \( 710(5d + 6) \), you distribute \( 710 \) to both terms inside the parentheses:
\[ 710(5d + 6) = 710 \cdot 5d + 710 \cdot 6 \]
This simplifies to:
\[ 3550d + 4260 \]
So, the expanded form of \( 710(5d + 6) \) is \( 3550d + 4260 \).
To expand \(\frac{7}{10}(5d + 6)\), you distribute \(\frac{7}{10}\) to both terms inside the parentheses:
\[ \frac{7}{10}(5d) + \frac{7}{10}(6) \]
Calculating each term:
So, the expanded form is:
\[ \frac{7}{2}d + \frac{21}{5} \]
Thus, the correct response from your options is:
\(\frac{7}{2}d + \frac{21}{5}\).