Expand 6(x+1)

11 answers

To expand \( 6(x + 1) \), you distribute the 6 to both terms inside the parentheses:

\[ 6(x + 1) = 6 \cdot x + 6 \cdot 1 \]

This simplifies to:

\[ 6x + 6 \]

So, the expanded form of \( 6(x + 1) \) is \( 6x + 6 \).

So what’s the answer

The expanded form of \( 6(x + 1) \) is \( 6x + 6 \).

Expand 4(3z−7)

To expand \( 4(3z - 7) \), you distribute the 4 to both terms inside the parentheses:

\[ 4(3z - 7) = 4 \cdot 3z + 4 \cdot (-7) \]

This simplifies to:

\[ 12z - 28 \]

So, the expanded form of \( 4(3z - 7) \) is \( 12z - 28 \).

Expand −5(2q+8)

To expand \(-5(2q + 8)\), you distribute the \(-5\) to both terms inside the parentheses:

\[ -5(2q + 8) = -5 \cdot 2q + (-5) \cdot 8 \]

This simplifies to:

\[ -10q - 40 \]

So, the expanded form of \(-5(2q + 8)\) is \(-10q - 40\).

Expand 710(5d+6) .

To expand \( 710(5d + 6) \), you distribute \( 710 \) to both terms inside the parentheses:

\[ 710(5d + 6) = 710 \cdot 5d + 710 \cdot 6 \]

This simplifies to:

\[ 3550d + 4260 \]

So, the expanded form of \( 710(5d + 6) \) is \( 3550d + 4260 \).

Expand 7/10(5d+6).(1 point)
Responses

35d + 6
35d + 6

5d + 21/5
5 d + 21 fifths

35d + 42
35d + 42

7/2d + 21/5

To expand \(\frac{7}{10}(5d + 6)\), you distribute \(\frac{7}{10}\) to both terms inside the parentheses:

\[ \frac{7}{10}(5d) + \frac{7}{10}(6) \]

Calculating each term:

  1. \(\frac{7}{10} \cdot 5d = \frac{35}{10}d = 3.5d\) or \(\frac{7}{2}d\) when simplified.
  2. \(\frac{7}{10} \cdot 6 = \frac{42}{10} = \frac{21}{5}\) when simplified.

So, the expanded form is:

\[ \frac{7}{2}d + \frac{21}{5} \]

Thus, the correct response from your options is:

\(\frac{7}{2}d + \frac{21}{5}\).