Expand 6(x +1)

11 answers

To expand 6(x + 1), we can use the distributive property.

6 multiplied by each term inside the parentheses:

6(x) + 6(1)

This gives us:

6x + 6
Expand 4(3z - 7)
To expand 4(3z - 7), we need to apply the distributive property.

4 multiplied by each term inside the parentheses:

4(3z) - 4(7)

This gives us:

12z - 28
Expand -5(2q+8)
To expand -5(2q + 8), we use the distributive property.

-5 multiplied by each term inside the parentheses:

-5(2q) - 5(8)

This gives us:

-10q - 40
Expand 7 over 10 (5d+6)
To expand 7/10(5d + 6), we can use the distributive property.

Multiply 7/10 by each term inside the parentheses:

(7/10)(5d) + (7/10)(6)

This gives us:

35d/10 + 42/10

Simplifying by combining like terms in the numerator and denominator gives us:

(35d + 42)/10
Expand-5/8 (3p+8)
To expand -5/8(3p + 8), we can use the distributive property.

Multiply -5/8 by each term inside the parentheses:

(-5/8)(3p) + (-5/8)(8)

This gives us:

-15p/8 - 40/8

Simplifying by combining like terms in the numerator and denominator gives us:

(-15p - 40)/8
U sure?
Apologies for the confusion in my previous response. Let's correct it.

To expand -5/8(3p + 8), we use the distributive property.

Multiply -5/8 by each term inside the parentheses:

(-5/8)(3p) + (-5/8)(8)

This gives us:

-15p/8 - 40/8

Simplifying the terms in the numerator:

-15p - 40/8

To further simplify, we can simplify the numerator:

(-15p - 40)/8
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