To expand 6(x + 1), we need to distribute the 6 to both terms inside the parentheses:
6(x + 1) = 6*x + 6*1
This simplifies to:
6x + 6.
Expand 6(x + 1).
39 answers
Expand 4(3z − 7).
To expand 4(3z − 7), we need to distribute the 4 to both terms inside the parentheses:
4(3z − 7) = 4*3z - 4*7
This simplifies to:
12z - 28.
4(3z − 7) = 4*3z - 4*7
This simplifies to:
12z - 28.
Expand −5(2q + 8).
To expand -5(2q + 8), we need to distribute the -5 to both terms inside the parentheses:
-5(2q + 8) = -5*2q - 5*8
This simplifies to:
-10q - 40.
-5(2q + 8) = -5*2q - 5*8
This simplifies to:
-10q - 40.
Expand 7/10(5d+6)
To expand 7/10(5d+6), we need to distribute the 7/10 to both terms inside the parentheses:
7/10(5d+6) = (7/10)*5d + (7/10)*6
This simplifies to:
(35/10)d + (42/10)
Simplifying further, we can reduce the fractions:
(35/10)d + (42/10) = (7/2)d + (21/5)
7/10(5d+6) = (7/10)*5d + (7/10)*6
This simplifies to:
(35/10)d + (42/10)
Simplifying further, we can reduce the fractions:
(35/10)d + (42/10) = (7/2)d + (21/5)
Expand −58(3p+8)
To expand -58(3p + 8), we need to distribute the -58 to both terms inside the parentheses:
-58(3p + 8) = -58*3p - 58*8
This simplifies to:
-174p - 464.
-58(3p + 8) = -58*3p - 58*8
This simplifies to:
-174p - 464.
Expand −5/8(3p+8).
To expand -5/8(3p + 8), we need to distribute the -5/8 to both terms inside the parentheses:
-5/8(3p + 8) = -5/8 * 3p - 5/8 * 8
This simplifies to:
-15/8p - 5/1 * 8/8
The term -5/1 * 8/8 equals -40/8 or -5.
So, the expanded form is:
-15/8p - 5.
-5/8(3p + 8) = -5/8 * 3p - 5/8 * 8
This simplifies to:
-15/8p - 5/1 * 8/8
The term -5/1 * 8/8 equals -40/8 or -5.
So, the expanded form is:
-15/8p - 5.
Expand 5(y + 2) using the distributive property.
To expand 5(y + 2) using the distributive property, we multiply 5 by both terms inside the parentheses:
5(y + 2) = 5 * y + 5 * 2
This simplifies to:
5y + 10.
5(y + 2) = 5 * y + 5 * 2
This simplifies to:
5y + 10.
Expand −5(−3 − 11g).
To expand -5(-3 - 11g), we need to distribute the -5 to both terms inside the parentheses:
-5(-3 - 11g) = -5*(-3) - 5*(-11g)
This simplifies to:
15 + 55g.
So, the expanded form is:
15 + 55g.
-5(-3 - 11g) = -5*(-3) - 5*(-11g)
This simplifies to:
15 + 55g.
So, the expanded form is:
15 + 55g.
Expand 13(q−6) using the Distributive Property.
To expand 13(q - 6) using the distributive property, we need to distribute 13 to both terms inside the parentheses:
13(q - 6) = 13 * q - 13 * 6
This simplifies to:
13q - 78.
So, the expanded form is:
13q - 78.
13(q - 6) = 13 * q - 13 * 6
This simplifies to:
13q - 78.
So, the expanded form is:
13q - 78.
Expand 1/3(q−6) using the Distributive Property.
To expand 1/3(q - 6) using the distributive property, we need to distribute 1/3 to both terms inside the parentheses:
1/3(q - 6) = (1/3) * q - (1/3) * 6
This simplifies to:
q/3 - 6/3
Simplifying further, we get:
q/3 - 2
So, the expanded form is:
q/3 - 2.
1/3(q - 6) = (1/3) * q - (1/3) * 6
This simplifies to:
q/3 - 6/3
Simplifying further, we get:
q/3 - 2
So, the expanded form is:
q/3 - 2.
Expand 2/5(−5c+10).
To expand 2/5(-5c + 10) using the distributive property, we need to distribute 2/5 to both terms inside the parentheses:
2/5(-5c + 10) = (2/5) * (-5c) + (2/5) * (10)
Simplifying:
-10c/5 + 20/5
Simplifying further, we have:
-2c + 4
So, the expanded form is:
-2c + 4.
2/5(-5c + 10) = (2/5) * (-5c) + (2/5) * (10)
Simplifying:
-10c/5 + 20/5
Simplifying further, we have:
-2c + 4
So, the expanded form is:
-2c + 4.
Expand −7/6(3g+2).
To expand -7/6(3g + 2) using the distributive property, we need to distribute -7/6 to both terms inside the parentheses:
-7/6(3g + 2) = (-7/6) * 3g + (-7/6) * 2
Simplifying:
-21g/6 - 14/6
Simplifying further, we have:
-7g/2 - 7/3
So, the expanded form is:
-7g/2 - 7/3.
-7/6(3g + 2) = (-7/6) * 3g + (-7/6) * 2
Simplifying:
-21g/6 - 14/6
Simplifying further, we have:
-7g/2 - 7/3
So, the expanded form is:
-7g/2 - 7/3.
Expand −5(2q + 8)
To expand −5(2q + 8), we need to distribute the −5 to both terms inside the parentheses:
−5(2q + 8) = −5 * 2q − 5 * 8
This simplifies to:
−10q − 40.
So, the expanded form is −10q − 40.
−5(2q + 8) = −5 * 2q − 5 * 8
This simplifies to:
−10q − 40.
So, the expanded form is −10q − 40.
Expand 5(y + 2) using the distributive property.(1 point)
Responses
6y + 7
6 y plus 7
5y + 10
5 y plus 10
5y + 2
5 y plus 2
6y + 10
Responses
6y + 7
6 y plus 7
5y + 10
5 y plus 10
5y + 2
5 y plus 2
6y + 10
The correct answer is 5y + 10.
Expand −5(−3 − 11g).(1 point)
Responses
55g − 15
55 g minus 15
−55g + 15
negative 55 g plus 15
−55g − 15
negative 55 g minus 15
55g + 15
Responses
55g − 15
55 g minus 15
−55g + 15
negative 55 g plus 15
−55g − 15
negative 55 g minus 15
55g + 15
The correct answer is 55g + 15.
Expand 1/3(q−6) using the Distributive Property.(1 point)
Responses
1/3q−6
Start Fraction 1 over 3 End Fraction q minus 6
1/3q−2
Start Fraction 1 over 3 End Fraction q minus 2
−1/3q+2
negative Start Fraction 1 over 3 End Fraction q plus 2
−1/3q+6
Responses
1/3q−6
Start Fraction 1 over 3 End Fraction q minus 6
1/3q−2
Start Fraction 1 over 3 End Fraction q minus 2
−1/3q+2
negative Start Fraction 1 over 3 End Fraction q plus 2
−1/3q+6
The correct answer is 1/3q - 2.
Expand 2/5(−5c+10).(1 point)
Responses
2c−4
2c minus 4
−2c+4
negative 2c plus 4
−2c+10
negative 2c plus 10
2c−10
Responses
2c−4
2c minus 4
−2c+4
negative 2c plus 4
−2c+10
negative 2c plus 10
2c−10
The correct answer is -2c + 4.
Expand −7/6(3g+2).(1 point)
Responses
7/2g−73
Start Fraction 7 over 2 End Fraction g minus Start Fraction 7 over 3 End Fraction
−7/2g−73
negative Start Fraction 7 over 2 End Fraction g minus Start Fraction 7 over 3 End Fraction
7/2g+2
Start Fraction 7 over 2 End Fraction g plus 2
−72g+2
Responses
7/2g−73
Start Fraction 7 over 2 End Fraction g minus Start Fraction 7 over 3 End Fraction
−7/2g−73
negative Start Fraction 7 over 2 End Fraction g minus Start Fraction 7 over 3 End Fraction
7/2g+2
Start Fraction 7 over 2 End Fraction g plus 2
−72g+2
The correct answer is -7/2g - 7/3.
Which of the following answers applies the Distributive Property of Multiplication Over Addition correctly for simplifying 23−9(2x+5)+11x ?(1 point)
Responses
23−7x−4+11x
23 minus 7 x minus 4 plus 11 x
23−18x−45+11x
23 minus 18 x minus 45 plus 11 x
14(2x+5)+11x
14 left parenthesis 2 x plus 5 right parenthesis plus 11 x
14(2x+5+11x)
Responses
23−7x−4+11x
23 minus 7 x minus 4 plus 11 x
23−18x−45+11x
23 minus 18 x minus 45 plus 11 x
14(2x+5)+11x
14 left parenthesis 2 x plus 5 right parenthesis plus 11 x
14(2x+5+11x)
Simplify 2(3v+9)−14−6(−5v−4) .(1 point)
Responses
106v+98
106 v plus 98
36v+28
36 v plus 28
−6v−13
negative 6 v minus 13
−24v−20
Responses
106v+98
106 v plus 98
36v+28
36 v plus 28
−6v−13
negative 6 v minus 13
−24v−20
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can i have answers for the whole assesment tho