Expand 5(y + 2) using the distributive property.(1 point)%0D%0AResponses%0D%0A%0D%0A5y + 10%0D%0A5 y plus 10%0D%0A%0D%0A6y + 7%0D%0A6 y plus 7%0D%0A%0D%0A5y + 2%0D%0A5 y plus 2%0D%0A%0D%0A6y + 10

Answer 1

To expand \(5(y + 2)\) using the distributive property, you multiply 5 by each term inside the parentheses:

\[ 5(y + 2) = 5 \cdot y + 5 \cdot 2 = 5y + 10 \]

So the correct answer is:

5y + 10 (or 5 y plus 10).

Answer 2

Expand −5(−3 − 11g).(1 point)%0D%0AResponses%0D%0A%0D%0A−55g − 15%0D%0Anegative 55 g minus 15%0D%0A%0D%0A−55g + 15%0D%0Anegative 55 g plus 15%0D%0A%0D%0A%E2%80%8B%E2%80%8B%E2%80%8B55g − 15%0D%0A55 g minus 15%0D%0A%0D%0A55g + 15

Answer 3

To expand \(-5(-3 - 11g)\) using the distributive property, you multiply \(-5\) by each term inside the parentheses:

\[ -5(-3 - 11g) = -5 \cdot (-3) + (-5) \cdot (-11g) \]

Calculating each term:

1. \(-5 \cdot (-3) = 15\)
2. \(-5 \cdot (-11g) = 55g\)

Putting it all together:

\[ -5(-3 - 11g) = 15 + 55g \]

So the final result can be written as \(55g + 15\), which is the same as 55g plus 15.

However, note that if we list in standard form usually it is \(55g + 15\). Therefore, the answer is:

55g + 15 (or 55 g plus 15).

Answer 4

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Answer 5

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