Expand 5(y + 2) using the distributive property.(1 point)

Responses

6y + 10
6 y plus 10

6y + 7
6 y plus 7

5y + 10
5 y plus 10

5y + 2
5 y plus 2

11 answers

To expand \( 5(y + 2) \) using the distributive property, you multiply 5 by each term inside the parentheses:

\[ 5(y + 2) = 5 \cdot y + 5 \cdot 2 = 5y + 10. \]

So, the correct response is:

5y + 10 (or 5 y plus 10).

Expand −5(−3 − 11g).(1 point)
Responses

55g + 15
55 g plus 15

​​​55g − 15
55 g minus 15

−55g + 15
negative 55 g plus 15

−55g − 15

To expand \(-5(-3 - 11g)\) using the distributive property, you multiply \(-5\) by each term inside the parentheses:

\[ -5(-3 - 11g) = -5 \cdot (-3) + -5 \cdot (-11g) = 15 + 55g. \]

So, rewriting it gives:

\[ 55g + 15. \]

The correct response is:

55g + 15 (or 55 g plus 15).

Expand 1/3(q−6) using the Distributive Property.(1 point)
Responses

−1/3q+6
negative Start Fraction 1 over 3 End Fraction q plus 6

1/3q−6
Start Fraction 1 over 3 End Fraction q minus 6

−1/3q+2
negative Start Fraction 1 over 3 End Fraction q plus 2

1/3q−2

To expand \(\frac{1}{3}(q - 6)\) using the distributive property, you multiply \(\frac{1}{3}\) by each term inside the parentheses:

\[ \frac{1}{3}(q - 6) = \frac{1}{3}q + \frac{1}{3}(-6) = \frac{1}{3}q - 2. \]

So, the correct response is:

\(\frac{1}{3}q - 2\) (or Start Fraction 1 over 3 End Fraction q minus 2).

Expand 25(−5c+10).(1 point)
Responses

2c−10
2c minus 10

−2c+10
negative 2c plus 10

2c−4
2c minus 4

−2c+4

To expand \( 25(-5c + 10) \) using the distributive property, you multiply \( 25 \) by each term inside the parentheses:

\[ 25(-5c + 10) = 25 \cdot (-5c) + 25 \cdot 10. \]

Calculating each term:

\[ 25 \cdot (-5c) = -125c, \] \[ 25 \cdot 10 = 250. \]

So, combining these results gives:

\[ -125c + 250. \]

This does not match any of the provided options. If we simplify further (and perhaps there was a misunderstanding in the given problem or options), we can state that:

The expanded expression is \(-125c + 250\), but does not match any of the responses you provided. If you wanted a specific outcome, please verify the original expression or intended values.

Expand 2/5(−5c+10).(1 point)
Responses

2c−10
2c minus 10

−2c+10
negative 2c plus 10

2c−4
2c minus 4

−2c+4

To expand \(\frac{2}{5}(-5c + 10)\) using the distributive property, we multiply \(\frac{2}{5}\) by each term inside the parentheses:

\[ \frac{2}{5}(-5c + 10) = \frac{2}{5} \cdot (-5c) + \frac{2}{5} \cdot 10. \]

Calculating each term:

  1. For \(\frac{2}{5} \cdot (-5c)\): \[ \frac{2 \cdot -5c}{5} = -2c. \]

  2. For \(\frac{2}{5} \cdot 10\): \[ \frac{2 \cdot 10}{5} = \frac{20}{5} = 4. \]

Combining these results gives: \[ -2c + 4. \]

So, the correct response is:

\(-2c + 4\) (or negative 2c plus 4).

Expand −7/6(3g+2).(1 point)
Responses

72g+2
Start Fraction 7 over 2 End Fraction g plus 2

−7/2g−7/3
negative Start Fraction 7 over 2 End Fraction g minus Start Fraction 7 over 3 End Fraction

7/2g−7/3
Start Fraction 7 over 2 End Fraction g minus Start Fraction 7 over 3 End Fraction

−7/2g+2

To expand \(-\frac{7}{6}(3g + 2)\) using the distributive property, we multiply \(-\frac{7}{6}\) by each term inside the parentheses:

\[ -\frac{7}{6}(3g + 2) = -\frac{7}{6} \cdot 3g + -\frac{7}{6} \cdot 2. \]

Calculating each term:

  1. For \(-\frac{7}{6} \cdot 3g\): \[ -\frac{7 \cdot 3g}{6} = -\frac{21}{6}g = -\frac{7}{2}g \quad \text{(simplifying by dividing the numerator and denominator by 3)}. \]

  2. For \(-\frac{7}{6} \cdot 2\): \[ -\frac{7 \cdot 2}{6} = -\frac{14}{6} = -\frac{7}{3} \quad \text{(simplifying by dividing the numerator and denominator by 2)}. \]

Combining these results gives: \[ -\frac{7}{2}g - \frac{7}{3}. \]

So, the correct response is:

\(-\frac{7}{2}g - \frac{7}{3}\) (or negative Start Fraction 7 over 2 End Fraction g minus Start Fraction 7 over 3 End Fraction).