Expand −5/6(9b−12) . Fill in the blanks to complete the expanded expression.

11 answers

To expand the expression \(-\frac{5}{6}(9b - 12)\), you will distribute \(-\frac{5}{6}\) to both terms inside the parentheses:

  1. Multiply \(-\frac{5}{6}\) by \(9b\): \[ -\frac{5}{6} \cdot 9b = -\frac{45}{6}b = -\frac{15}{2}b \]

  2. Multiply \(-\frac{5}{6}\) by \(-12\): \[ -\frac{5}{6} \cdot -12 = \frac{5 \cdot 12}{6} = \frac{60}{6} = 10 \]

Now, combine the results: \[ -\frac{5}{6}(9b - 12) = -\frac{15}{2}b + 10 \]

So, the completed expanded expression is: \[ -\frac{15}{2}b + 10 \]

what is the final answer

The final expanded expression for \(-\frac{5}{6}(9b - 12)\) is:

\[ -\frac{15}{2}b + 10 \]

Find the GCF of 20x − 4 .

To find the greatest common factor (GCF) of the expression \(20x - 4\), we first look for the GCF of the coefficients of the terms.

  1. The coefficients are \(20\) and \(-4\).
  2. The GCF of \(20\) and \(4\) is \(4\).

Next, we can factor \(4\) out of the expression:

\[ 20x - 4 = 4(5x - 1) \]

So, the GCF of \(20x - 4\) is \(4\).

Find the GCF of 30m + 12n .

To find the greatest common factor (GCF) of the expression \(30m + 12n\), we need to determine the GCF of the coefficients \(30\) and \(12\).

  1. Find the GCF of the coefficients:

    • The factors of \(30\) are \(1, 2, 3, 5, 6, 10, 15, 30\).
    • The factors of \(12\) are \(1, 2, 3, 4, 6, 12\).
    • The common factors are \(1, 2, 3, 6\).
    • The greatest of these is \(6\).
  2. Factor out the GCF: Now that we know the GCF is \(6\), we can factor it out from the expression: \[ 30m + 12n = 6(5m + 2n) \]

Thus, the GCF of \(30m + 12n\) is \(6\).

whats the final answer

The greatest common factor (GCF) of \(30m + 12n\) is 6.

Factor 12y+6 using the GCF.

To factor the expression \(12y + 6\) using the greatest common factor (GCF):

  1. Find the GCF of the coefficients:

    • The coefficients are \(12\) and \(6\).
    • The GCF of \(12\) and \(6\) is \(6\).
  2. Factor out the GCF: Now that we know the GCF is \(6\), we can factor it out from the expression: \[ 12y + 6 = 6(2y + 1) \]

Therefore, the factored form of \(12y + 6\) is: \[ \boxed{6(2y + 1)} \]

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