To balance the equation \( \text{NaCl} + \text{CaF}_2 \rightarrow \text{NaF} + \text{CaCl}_2 \), we need to ensure that the number of each type of atom on the reactant side is equal to the number on the product side.
Let's break it down:
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On the left side (reactants):
- Sodium (Na): 1 (from NaCl)
- Chlorine (Cl): 1 (from NaCl)
- Calcium (Ca): 1 (from CaF2)
- Fluorine (F): 2 (from CaF2)
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On the right side (products):
- Sodium (Na): 1 (from NaF)
- Fluorine (F): 1 (from NaF)
- Calcium (Ca): 1 (from CaCl2)
- Chlorine (Cl): 2 (from CaCl2)
Now we can start balancing:
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Balance Sodium (Na):
- Both sides have 1 Na, so Na is balanced.
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Balance Calcium (Ca):
- Both sides have 1 Ca, so Ca is balanced.
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Balance Chlorine (Cl):
- Left has 1 Cl, right has 2 Cl. We can place a coefficient of 2 in front of NaCl: \[ 2 \text{NaCl} + \text{CaF}_2 \rightarrow \text{NaF} + \text{CaCl}_2 \]
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Re-evaluate Sodium (Na) and Fluorine (F):
- Now, we have 2 Na on the left (from 2 NaCl), and we need 2 NaF to balance: \[ 2 \text{NaCl} + \text{CaF}_2 \rightarrow 2 \text{NaF} + \text{CaCl}_2 \]
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Balance Fluorine (F):
- On the left, we still have 2 F in \( \text{CaF}_2 \), and now we added 2 NaF on the right, which gives us 2 F, so F is now balanced as well.
The final balanced equation is: \[ 2 \text{NaCl} + 1 \text{CaF}_2 \rightarrow 2 \text{NaF} + 1 \text{CaCl}_2 \]
Thus, the coefficients in sequence from left to right are: 2, 1, 2, 1.
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