Here are the answers to each of the questions based on the transformations and reflections described:
Question 1:
For the triangle with vertices B(−3, 0), C(2, −1), D(−1, 2) and needing to find the transformation to produce B″(−2, 1), C″(3, 2), D″(0, −1):
To achieve this transformation, it looks like:
- Reflecting over the x-axis: changes the y-values' signs (A point (x, y) becomes (x, -y)).
- Translating: shifts the points.
From examining the options:
- The option
(x, y) → (−x, y) → (x + 2, y + 2)
seems correct because reflecting will flip y-values, after which the translation aligns the points correctly.
Correct Answer:
(x, y) → (−x, y) → (x + 2, y + 2)
Question 2:
For trapezoid JKLM and translating the point L(−2, −5) using the rule (x, y) → (x + 8, y − 3):
Calculating for point L′:
- L′ = (−2 + 8, −5 - 3)
- L′ = (6, -8)
Correct Answer:
(6, −8)
Question 3:
Comparing the two pentagons ABCDE and A″B″C″D″E″, we need the transformations that yield the output.
The point transformation requires that the two transformations include a translation and a reflection.
Analyzing the choices:
- Reflecting across the y-axis will change x-values, and then you need to translate them correctly.
The transformation (x, y) → (x + 2, y + 8) and reflected across the y-axis
is plausible. Each coordinate seems to increment as required.
Correct Answer:
Translated according to the rule (x, y) → (x + 2, y + 8) and reflected across the y-axis
Question 4:
Triangle ABC with side BC of length 2, reflected over the y-axis to create triangle A′B′C′. The lengths of sides are preserved when reflecting across the y-axis.
Thus, if BC is of length 2,
- B′C′ will also be 2.
Correct Answer:
B′C′ = 2
I hope this helps, and let me know if you have further questions!