Even when a mechanism is consistent with the rate law , later experimentation may it to be incorrect or only one of several alternative. As an example, the reaction between hydrogen and iodine has the following rate law: rate=k[H]^3[I]2.

The long accepted mechanism proposed a single
Biomolecular step, that is, the overall reaction was though to be elementary:
H2(g)+i2(g)-> 2HI (g)
In the 1960's, however, spectroscopy evidence showed the presence of free I atom during the reaction kineticists have since proposed a three step mechanism:
(1) I ^2(g)<-> 2i (g) [fast]
(2) H^2(g)+I(g)->H^2I (g)[fast]
(3)H^2i (g)+I(g)-> 2HI (g) [slow]
Show that this mechanism is consistent with the rate law.

Similar Questions
  1. True or False:1. A rate law can be written from the molecularity of the slowest elementary step. 2.The final rate law can
    1. answers icon 0 answers
  2. The overall rate of any chemical reaction is most closely related toa) the number of steps in the reaction mechanism b)the
    1. answers icon 3 answers
    1. answers icon 0 answers
  3. I am supposed to create a "possible" mechanism for the reaction2A + B --> 2C when the rate law is Rate=k[A][B]^2. This mechanism
    1. answers icon 0 answers
more similar questions