Asked by Munavvar

Even when a mechanism is consistent with the rate law , later experimentation may it to be incorrect or only one of several alternative. As an example, the reaction between hydrogen and iodine has the following rate law: rate=k[H]^3[I]2.
The long accepted mechanism proposed a single
Biomolecular step, that is, the overall reaction was though to be elementary:
H2(g)+i2(g)-> 2HI (g)
In the 1960's, however, spectroscopy evidence showed the presence of free I atom during the reaction kineticists have since proposed a three step mechanism:
(1) I ^2(g)<-> 2i (g) [fast]
(2) H^2(g)+I(g)->H^2I (g)[fast]
(3)H^2i (g)+I(g)-> 2HI (g) [slow]
Show that this mechanism is consistent with the rate law.

Answers

There are no human answers yet.
There are no AI answers yet. The ability to request AI answers is coming soon!

Related Questions