To evaluate \(3^{-3}\), we can use the property of negative exponents, which states that \(a^{-n} = \frac{1}{a^n}\).
Applying this to our problem:
\[ 3^{-3} = \frac{1}{3^3} \]
Now we calculate \(3^3\):
\[ 3^3 = 3 \times 3 \times 3 = 27 \]
Thus, we have:
\[ 3^{-3} = \frac{1}{27} \]
Therefore, the final answer is:
\[ \frac{1}{27} \]
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