To evaluate which expression is equivalent to \(\frac{\log x}{\log 4}\), we will use the change of base formula for logarithms, which states:
\[ \log_b a = \frac{\log_k a}{\log_k b} \]
for any base \(k\).
Using this, we can rewrite \(\frac{\log x}{\log 4}\) as:
\[ \frac{\log x}{\log 4} = \log_4 x \]
Now, let's analyze each option provided:
-
\( \frac{\log_x x}{\log 4} \)
- Here, \(\log_x x = 1\) (since any log of a number to its own base is 1).
- So, \( \frac{1}{\log 4} \) is not equivalent to \(\frac{\log x}{\log 4}\).
-
\( \frac{\log_3 x}{\log_3 4} \)
- This can be rewritten using the change of base formula: \(\frac{\log_3 x}{\log_3 4} = \log_4 x\), which is equivalent to \(\frac{\log x}{\log 4}\). This is a potential match.
-
\( \log_x 4 \)
- This is not equivalent to \(\frac{\log x}{\log 4}\).
-
\( \frac{\ln x}{\ln 4} \)
- This can also be rewritten using the change of base formula: \(\frac{\ln x}{\ln 4} = \log_4 x\), which is the same as \(\frac{\log x}{\log 4}\) since \(\log\) and \(\ln\) are simply logs with different bases. This is also a potential match.
Summarizing:
- The expressions that are equivalent to \(\frac{\log x}{\log 4}\) are:
- \( \frac{\log_3 x}{\log_3 4} \)
- \( \frac{\ln x}{\ln 4} \)
Therefore, both options 2 and 4 are correct equivalences of \(\frac{\log x}{\log 4}\).