Integral of: (cos(lnx)/x)dx
let u = ln x
du = dx/x
Your integral is therefore that of
cos u du, which is sin u = sin(ln x)
Try the others yourself. In the first one, I would let x^2 = u
Evaluate using u-substitution:
Integral of: 4x(tan(x^2))dx
Integral of: (1/(sqrt(x)*x^(sqrt(x))))dx
Integral of: (cos(lnx)/x)dx
2 answers
Integral 3x/x2(x-2)dx