Yes, they are both 0, but your reasoning baffles me
what is " cos(t) = x" supposed to mean ?
The hint was to use the period
9π/2
= 4π + 1/2 π
so we have 2 full rotations plus another half
cos(9π/2) = cos(π/2) = 0
Evaluate the two trigonometric functions using its period as an aid.
1. cos (9pi/2) = ?
Ans: 0
2. cos (-9pi/2) = ?
Ans: 0
I think they are both 0 because cos(t) = x.
2 answers
cos(t) = x refers to the x-value found on the unit circle for the corresponding radian measure. So pi/2 has the x value of 0 on the unit circle.
2 answers