To evaluate Column A and Column B, we will calculate each sum step-by-step.
Column A: \[ 0.5 + \frac{3}{4} \]
Convert \(0.5\) to a fraction: \[ 0.5 = \frac{1}{2} \]
Now add \(\frac{1}{2}\) and \(\frac{3}{4}\): To add these fractions, we need a common denominator. The least common denominator of \(2\) and \(4\) is \(4\): \[ \frac{1}{2} = \frac{2}{4} \]
Now add: \[ \frac{2}{4} + \frac{3}{4} = \frac{2+3}{4} = \frac{5}{4} \]
Column A Sum: \[ \frac{5}{4} \quad \text{(This is a rational number.)} \]
Column B: \[ \sqrt{3} + \frac{2}{5} \]
Here, \(\sqrt{3}\) is an irrational number, while \(\frac{2}{5}\) is a rational number.
The sum of an irrational number and a rational number is always irrational. Thus: \[ \sqrt{3} + \frac{2}{5} \quad \text{(This is an irrational number.)} \]
Conclusion:
- Column A has a sum of \(\frac{5}{4}\) which is rational.
- Column B has a sum of \(\sqrt{3} + \frac{2}{5}\) which is irrational.
So, the true statement is:
Statement #1: Only Column A has a rational sum.
Therefore, the answer is Statement #1.