Evaluate the surface integral

S F · dS
for the given vector field F and the oriented surface S. In other words, find the flux of F across S. For closed surfaces, use the positive (outward) orientation.
F(x, y, z) = x i + y j + z4 k
S is the part of the cone
z = sqrt(x2 + y2)
beneath the plane
z = 3
with upward orientation

1 answer

I got 261 PI
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