the way you typed it, it would mean y = 0 , since log1 = 0
if you meant
y = log(1/7^x) then
y = log1 - log7^x
= 0 - xlog7
= -0.8451x which is a straight line
or perhaps did you mean y = (log (1/7))^x ?
- can you see the ambiguity of the question if no brackets are used?
Evaluate the logarithmic equation for three values of x that are greater than 1, three values of x that are between 0 and 1, and at x=1. Show your work. Use the resulting ordered pairs to plot the graph. State the equation of the line asymptotic to the graph (if any).
y= log 1/7^x
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