Do you mean log(base2)of x?
log2(0.001) = log10(.001)/log10(2) = -3/.30103 = -9.97
log2(0.01) = -6.64
log2(0.1) = -3.32
log2(1) = 0
You do the graphing and submitting.
As x-> 0, log2(x) -> -infinity
The negative y axis is the asymptote.
Evaluate the logarithmic equation for three values of x that are greater than 1, three values of x that are between 0 and 1, and at x=1. Show your work. Use the resulting ordered pairs to plot the graph; submit the graph via the Dropbox. State the equation of the line asymptotic to the graph y = log2 x
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